u^2+7u-70=0

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Solution for u^2+7u-70=0 equation: 



u^2+7u-70=0

a = 1; b = 7; c = -70;
Δ = b2-4ac
Δ = 72-4·1·(-70)
Δ = 329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{329}}{2*1}=\frac{-7-\sqrt{329}}{2}
$


$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{329}}{2*1}=\frac{-7+\sqrt{329}}{2}
$

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